MCQ
Propene and propyne can be distinguished by
- A$Br_2/CCl_4$
- BBaeyer's Reagent
- ✓$AgNO_3 + NH_4OH$
- D$O_3$
✓
Answer
Correct option: C.
$AgNO_3 + NH_4OH$
c
$C{H_3} - CH = C{H_2}\xrightarrow{{AgN{O_3} + N{H_4}OH}}$ No reaction
$C{H_3} - CH = C{H_2}\xrightarrow{{AgN{O_3} + N{H_4}OH}}$ No reaction
$C{H_3} - C \equiv CH\xrightarrow{{AgN{O_3} + N{H_4}OH}}\mathop {C{H_3} - C \equiv \bar C\,Ag}\limits_{white\,ppt} \downarrow $
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