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9. Hydricarbon — Chemistry STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceChemistry9. Hydricarbon1 Mark
MCQ
Propene when heated with chlorine at about $500\,^oC$ forms
  • ✓
    $CH_2Cl -CH = CH_2$
  • B
    $CH_3 -CHCl -CH_2Cl$
  • C
    $CH_2Cl-CHCl-CH_2Cl$
  • D
    All of these
✓

Answer

Correct option: A.
$CH_2Cl -CH = CH_2$
a
$C{{H}_{3}}-CH=C{{H}_{2}}+C{{l}_{2}}$ $\xrightarrow{500{{\,}^{o}}C}$ $\begin{matrix}
   C{{H}_{2}}-CH=C{{H}_{2}}+HCl  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
\end{matrix}$

This reaction is called allylic halogenation reaction becaus halogenation occurs at the allylic position of an alkene

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