MCQ
Propylene on hydrolysis with sulphuric acid forms
- A$n-$propyl alcohol
- ✓Isopropyl alcohol
- CEthyl alcohol
- DButyl alcohol
✓
Answer
Correct option: B.
Isopropyl alcohol
b
(b) $\mathop {C{H_2} = CH - C{H_3} + {H_2}O}\limits_{{\text{Propylene}}} \xrightarrow{{{H_2}S{O_4}}}$ $\mathop {C{H_3} - \mathop {\mathop C\limits^| H}\limits^{OH} - C{H_3}}\limits_{{\text{Isopropyl alcohol}}} $
(b) $\mathop {C{H_2} = CH - C{H_3} + {H_2}O}\limits_{{\text{Propylene}}} \xrightarrow{{{H_2}S{O_4}}}$ $\mathop {C{H_3} - \mathop {\mathop C\limits^| H}\limits^{OH} - C{H_3}}\limits_{{\text{Isopropyl alcohol}}} $
Thus in this reaction isopropyl alcohol is formed.
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