CBSE BoardEnglish MediumSTD 10MathsReal Numbers3 Marks
Question
Prove that $3+2\sqrt { 5 }$ is irrational.
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Answer
Let us assume, to the contrary, that is $3 + 2 \sqrt { 5 }$ rational. That is, we can find coprime integers a and b $( b \neq 0 )$ such that $3 + 2 \sqrt { 5 } = \frac { a } { b } \text { Therefore, } \frac { a } { b } - 3 = 2 \sqrt { 5 }$ $\Rightarrow \frac { a - 3 b } { b } = 2 \sqrt { 5 }$ $\Rightarrow \frac { a - 3 b } { 2 b } = \sqrt { 5 } \Rightarrow \frac { a } { 2 b } - \frac { 3 } { 2 }$ Since a and b are integers, We get $\frac { a } { 2 b } - \frac { 3 } { 2 }$ is rational, also so $\sqrt { 5 }$ is rational. But this contradicts the fact that $\sqrt { 5 }$ is irrational. This contradiction arose because of our incorrect assumption that $3 + 2 \sqrt { 5 }$ is rational. So, we conclude that $3 + 2 \sqrt { 5 }$ is irrational.
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