Question
Prove that: $\cos^2(\frac{\pi}{4}-\text{x})-\sin^2(\frac{\pi}{4}-\text{x})=\sin2\text{x}$

Answer

$\text{LHS}=\cos^2\Big(\frac{\pi}{4}-\text{x}\Big)-\sin^2\Big(\frac{\pi}{4}-\text{x}\Big)$ $=\cos2\Big(\frac{\pi}{4}-\text{x}\Big)$ $\Big[\because\cos2\text{x}=\cos^2\theta-\sin^2\text{x}\Big]$ $=\cos(\frac{\pi}{2}-2\text{x})$ $\Big[\because\cos\Big(\frac{\pi}{2}-\text{x}\Big)=\sin\text{x}\Big]$ $=\sin2\text{x}=\text{RHS}$

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