Question
Prove that:
$\frac{\cos(2\pi+\text{x})\text{cosec}(2\pi+\text{x})\tan\Big(\frac{\pi}{2}+\text{x}\Big)}{\sec\Big(\frac{\pi}{2}+\text{x}\Big)\cos\text{x}\cot(\pi+\text{x})}=1$

Answer

$\text{L.H.S}=\frac{\cos(2\pi+\text{x})\text{cosec}(2\pi+\text{x})\tan\Big(\frac{\pi}{2}+\text{x}\Big)}{\sec\Big(\frac{\pi}{2}+\text{x}\Big)\cos\text{x}\cot(\pi+\text{x})}$
$=\frac{\cos\text{x}\times\text{cosec }\text{x}(-\cot\text{x})}{-\text{cosec }\text{x}.\cos\text{x}\cot\text{x}}$ $\begin{pmatrix}\because\tan\Big(\frac{\pi}{2}+\text{x}\Big)=-\cot\text{x}\\\&\sec\Big(\frac{\pi}{2}+\text{x}\Big)=-\text{cosec}\text{x}\end{pmatrix}$
$= 1$
$= \text{R.H.S}$
$\text{Proved}$

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