Question
Prove that:
$\frac{\cos4\text{A}+\cos3\text{A}+\cos2\text{A}}{\sin4\text{A}+\sin3\text{A}+\sin2\text{A}}=\cot3\text{A}$
$\frac{\cos4\text{A}+\cos3\text{A}+\cos2\text{A}}{\sin4\text{A}+\sin3\text{A}+\sin2\text{A}}=\cot3\text{A}$
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Find $(\text{x}+1)^6+(\text{x}-1)^6.$ Hence or otherwise evaluate $(\sqrt2+1)^6+(\sqrt2-1).$
$4\text{x}^2+\text{y}^2-8\text{x}+2\text{y}+1=0$
$\text{f}(\text{x})=\frac{\cos\text{x}}{\text{x}}$