Question
Prove that $\frac{\cos (90-A)}{\sin A}=\frac{\sin (90-A)}{\cos A}$.
✓
Answer
$\text { L.H.S }=\frac{\cos (90-A)}{\sin A}$
$=\frac{\sin A}{\sin A}$
$=1$
$\text { R.H.S }=\frac{\sin (90-A)}{\cos A}$
$=\frac{\cos A}{\cos A}$
$=1$
$\therefore \text { L.H.S }=\text { R.H.S }$
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