Question
Prove that $sec \theta . cosec (90^\circ - \theta ) - \tan \theta . \cot( 90^\circ - \theta ) = 1.$
✓
Answer
$LHS = sec \theta . cosec (90^\circ - \theta ) - \tan \theta . \cot( 90^\circ - \theta )= sec \theta . sec \theta - \tan \theta . \tan \theta$
$= sec^2\theta - \tan^2\theta$
$= 1$
$= RHS$
Hence proved.
$= sec^2\theta - \tan^2\theta$
$= 1$
$= RHS$
Hence proved.
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