Question
Prove that: $\tan(-225^\circ)\cot(-405^\circ)-\tan(765^\circ)+\cot(675^\circ)=0$

Answer

$\text{L.H.S}=\tan(-225^\circ)\cot(-405^\circ)-\tan(-765)\cot(675^\circ)$ $=-\tan225^\circ(-\cot405^\circ)+\tan765^\circ\cot765\circ$ $\begin{pmatrix}\because\tan(-\theta)=-\tan\theta\\\&\cot(-\theta)=-\cot\theta\end{pmatrix}$ $=\tan\Big(\pi+\frac{\pi}{4}\Big)\cot\Big(2\pi\frac{\pi}{4}\Big)+\tan\Big(4\pi+\frac{\pi}{4}\Big)\cot\Big(4\pi-\frac{\pi}{4}\Big)$ $=\tan\frac{\pi}{4}\cot\frac{\pi}{4}+\tan\frac{\pi}{4}\times\Big(-\cot\frac{\pi}{4}\Big)$ $(\because\cot(4\pi-\theta)=-\cot\theta)$ $= 1. 1 + 1 (-1) $ $= 1 - 1$ $= 0$ $=\text{R.H.S}$ $\text{Proved}$

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