Question
Solve the inequality 3 (2 – x) $\ge$ 2 (1 – x) for real x.

Answer

Here $3(2 - x) \geqslant 2(1 - x)$
$ \Rightarrow 6 - 3x \geqslant 2 - 2x$
$ \Rightarrow - 3x + 2x \geqslant 2 - 6$
$ \Rightarrow - x \leqslant - 4$
Dividing both sides by -1, we have
$\frac{{ - x}}{{ - 1}} < \frac{{ - 4}}{{ - 1}} \Rightarrow x \leqslant 4$
Thus the solution set is $\left( { - \infty ,4} \right]$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free