Question
Prove that the function $f : R → R$ defined by $f (x) = 2x + 5$ is one-one.

Answer

Note that a function $f$ is one-one if
$f\left(x_1\right)=f\left(x_2\right) \Rightarrow x_1=x_2 \text { (definition of one-one function) }$
Now, given that $f\left(x_1\right)=f\left(x_2\right)$, i.e., $2 x_1+5=2 x_2+5$
$\Rightarrow 2 x_1+5-5=2 x_2+5-5$ (adding the same quantity on both sides)
$2 \mathrm{x}_1+0=2 \mathrm{x}_2+0$
$2 x_1=2 x_2$ (using additive identity of real number)
$\frac{2}{2} x_1=\frac{2}{2} x_2$ dividing by the same non zero quantity $\mathrm{x}_1=\mathrm{x}_2$
Hence, the given function is one one

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