In the given figure, AB is a diameter of the circle with centre O. DO is parallel to CB and ∠DCB = 120°.
Calculate : ∠DAB
Also show that the ΔAOD is an equilateral triangle .
Exercise 17 (A) | Q 38.1 | Page 260
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ABCD is a cyclic quadrilateral
∴ ∠DCB + ∠DAB = 180°
(pair of opposite angles in a cyclic quadrilateral are supplementary)
⇒ ∠DAB =180° -120° = 60°
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