Prove that:
the rhombus, inscribed in a circle, is a square.
Exercise 17 (A) | Q 20.2 | Page 259
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Let ABCD be a rhombus, inscribed in a circle
Now, ∠BAD = ∠BCD
(Opposite angles of a parallelogram are equal)
And ∠BAD = ∠BCD =180°
(pair of opposite angles in a cyclic quadrilateral are supplementary)
$\therefore \angle BAD =\angle BCD \frac{180^{\circ}}{2}=90^{\circ}$
∥y, the other two angles are 90° and all the sides
are equal.
∴ ABCD is a square.
art

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