Prove that: the rhombus, inscribed in a circle, is a square.
Exercise 17 (A) | Q 20.2 | Page 259
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Let ABCD be a rhombus, inscribed in a circle Now, ∠BAD = ∠BCD (Opposite angles of a parallelogram are equal) And ∠BAD = ∠BCD =180° (pair of opposite angles in a cyclic quadrilateral are supplementary) $\therefore \angle BAD =\angle BCD \frac{180^{\circ}}{2}=90^{\circ}$ ∥y, the other two angles are 90° and all the sides are equal. ∴ ABCD is a square.
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In the given figure, AB is a side of a regular six-sided polygon and AC is a side of a regular eight sided polygon inscribed in the circle with centre O. Calculate the sizes of:
(i) ∠AOB, (ii) ∠ACB (iii) ∠ABC
The figure given below, shows a circle with centre O. Given: ∠ AOC = a and ∠ ABC = b.
1. Find the relationship between a and b.
2. Find the measure of angle OAB, if OABC is a parallelogram.
If I is the incentre of triangle ABC and AI when produced meets the circumcircle of triangle ABC in point D. If ∠BAC = 66° and ∠ABC = 80°. Calculate : ∠DBC