Prove the following identities: - + = ^2 (1+ )^2 - Vidyadip

Question

Prove the following identities:
$\frac{\sec\theta-\tan\theta}{\sec\theta+\tan\theta}=\frac{\cos^2\theta}{(1+\sin\theta)^2}$

✓

Answer

$\text{LHS}=\frac{\sec\theta-\tan\theta}{\sec\theta+\tan\theta}$
$=\frac{\sec\theta-\tan\theta}{\sec\theta+\tan\theta}=\frac{\big(\frac{1}{\cos\theta}-\frac{\sin\theta}{\cos\theta}\big)}{\big(\frac{1}{\cos\theta}+\frac{\sin\theta}{\cos\theta}\big)}$
$=\frac{(1-\sin\theta)}{(1+\sin\theta)}$
$=\frac{(1+\sin\theta)}{(1+\sin\theta)}\times\frac{(1+\sin\theta)}{(1+\sin\theta)}$
$=\frac{1-\sin^2\theta}{(1+\sin\theta)^2}$
$=\frac{\cos^2\theta}{(1+\sin\theta)^2}$
$=\text{R.H.S.}$
$\therefore\text{R.H.S.}=\text{L.H.S.}$

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