$\begin{array}{ll} t =0 & 7\,g \\ t = t & 2\, g \end{array}$
at constant volume
$t =\frac{2.303}{ K } \log \frac{[ A ]_0}{[ A ]_{ t }}$
$=\frac{2 \cdot 303}{2 \cdot 011 \times 10^{-3}} \log \frac{7}{2}$
$=\frac{2 \cdot 303 \times 0 \cdot 544}{2 \cdot 011 \times 10^{-3}}$
$=622.989$
$\approx 623$
${A}+{B} \rightarrow {M}+{N}$ $......$ ${kJ} {mol}^{-1}$ બરાબર છે. (નજીકના પૂર્ણાંકમાં)
|
$[R] (molar)$ |
$1.0$ |
$0.76$ |
$0.40$ |
$0.10$ |
|
$t (min.)$ |
$0.0$ |
$0.05$ |
$0.12$ |
$0.18$ |
તો પ્રક્રિયાનો ક્રમ $...$ થશે.