MCQ
$PtCl_4 . 6H_2O$ can exist as a hydrated complex. Its $1\,molal$ aq. solution has depression in freezing point of $3.72$. Assume $100\%$ ionisation and $K_f\,(H_2O) = 1.86\,^oC\,mol^{-1}\,kg$, then complex is
- ✓$[Pt (H_2O)_6] \,Cl_4$
- B$[Pt(H_2O)_4Cl_2] \,Cl_2\, .\,2H_2O$
- C$[Pt(H_2O)_3Cl_3] \,Cl \,.\,3H_2O$
- D$[Pt(H_2O)_2Cl_4]\, .\,4H_2O$

