MCQ
$PtCl_4 . 6H_2O$ can exist as a hydrated complex. Its $1\,molal$ aq. solution has depression in freezing point of $3.72$. Assume $100\%$ ionisation and $K_f\,(H_2O) = 1.86\,^oC\,mol^{-1}\,kg$, then complex is
  • $[Pt (H_2O)_6] \,Cl_4$
  • B
    $[Pt(H_2O)_4Cl_2] \,Cl_2\, .\,2H_2O$
  • C
    $[Pt(H_2O)_3Cl_3] \,Cl \,.\,3H_2O$
  • D
    $[Pt(H_2O)_2Cl_4]\,  .\,4H_2O$

Answer

Correct option: A.
$[Pt (H_2O)_6] \,Cl_4$
a
$\Delta T _{ f }=(1+\alpha) K _{ f } m$

$\alpha=0.05=50 \times 10^{-3}$

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