MCQ
$[Pt(NH_3)(NH_2OH)(H_2O)(Py)]^+$ shows how many geometrical isomers
- A$2$
- ✓$3$
- C$6$
- D$5$

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[Atomic numbers of $Cr =24$ and $Mn =25$ ]
$(A)$ $Cr ^{2+}$ is a reducing agent
$(B)$ $Mn ^{3+}$ is an oxidizing agent
$(C)$ Both $Cr ^{2+}$ and $Mn ^{3+}$ exhibit $d^4$ electronic configuration
$(D)$ When $Cr ^{2+}$ is used as a reducing agent, the chromium ion attains $d^5$ electronic configuration
$\begin{array}{*{20}{c}} {{H_3}C - C{H_2} - CH - Et} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \end{array}$ about $C_2-C_3$ is (figure) 