MCQ
Pure $'N_2'$ obtain by
- A$N{H_4}N{O_2}\,\xrightarrow{\Delta }$
- B$N{H_4}N{O_3}\,\xrightarrow{\Delta }$
- C$(NH_4)_2Cr_2O_7\,\xrightarrow{\Delta }$
- ✓$NaN_3\,\xrightarrow{\Delta }$
$2 \mathrm{NaN}_{3} \stackrel{573 \mathrm{K}}{\longrightarrow} 2 \mathrm{Na}+3 \mathrm{N}_{2}$
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$(i)$ In pure water
$(ii)$ In presence of $0.1\ M AgNO_3$
$(iii)$ In presence of $2\ M aq.$ solution of $KCN$
$(iv)$ In presence of $ 1\ M aq$. solution of $Ca(CN)_2$
$(v)$ In presence of $2\ M aq.$ solution of $NH_3$
(Assuming $100\%$ dissociation of $AgNO_3, KCN$ and $Ca(CN)_2)$ and complex formation with $NH_3$ and $CN^-$ will take place.

phenol $\xrightarrow[{reaction}]{{\operatorname{Re} imer - Tiemann}}X\xrightarrow[{(ii)\,{H^ \oplus }}]{{(i)\,NaOH\,conc}}Z$
Product $Z$ is