MCQ
Pure $PCl_5$ is introduced into an evacuated chamber and comes to equilibrium at $247\,^oC$ and $2.0\  atm$. The equilibrium gaseous mixture contains $40\%$ chlorine by volume Calculate $K_p$ at $247\,^oC$ for the reaction $PCl_5(g) \rightleftharpoons  PCl_3(g) + Cl_2(g)$ .....$atm$
  • A
    $0.625$
  • B
    $4$
  • $1.6$
  • D
    $2$

Answer

Correct option: C.
$1.6$
c
$\mathrm{PCl}_{\mathrm{s}}(\mathrm{g}) \rightleftharpoons \mathrm{PCl}_{3}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{g})$
$\mathrm{K}_{\mathrm{p}}=\frac{\mathrm{P}_{\mathrm{PCl}_{3}} \mathrm{P}_{\mathrm{Cl}_{2}}}{\mathrm{P}_{\mathrm{PCl}_{5}}}=\frac{(0.4 \times 2)(0.4 \times 2)}{2 \times 0.2}$
$=0.4 \times 4=1.6$

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