MCQ
'$R$' formed in the following sequence of reaction is:


- A

- ✓

- C

- D








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Reason : Oxidation state of $Cr$ in $Na_2CrO_4$ is $+VI$
(Figure) $\xrightarrow[FeB{{r}_{3}}]{B{{r}_{2}}}B\xrightarrow{Sn\,/\,HCl}C$ $\xrightarrow[HCl]{NaN{{O}_{2}}}D\xrightarrow[HBr]{CuBr}E$