- ✓At. No. $58$ to $71$
- BAt. No. $21 $ to $30$
- CAt. No. $39$ to $ 71$
- DAt. No. $81$ to $91$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} O{\mkern 1mu} } \\
{\,\,\,|{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,\,\,\,\,{\mkern 1mu} {\mkern 1mu} ||} \\
{C{H_3} - CH - C - OH}
\end{array}$ $+ C{H_3} - N{H_2} \to 'A'\xrightarrow[\Delta ]{}'B'\xrightarrow{\begin{subarray}{l}
{\text{LiAl}}{{\text{H}}_4} \\
{\text{(excess)}}
\end{subarray} }'C'$
The final product $‘C’$ will be

$\begin{array}{*{20}{c}}
{O\,\,\,\,} \\
{||\,\,\,\,} \\
{C{H_3} - CH - C - C{H_2} - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{{C{F_3}COOOH}}[X]$ as main product
$[X]$ will be :
$(1)$ $C{H_3} - \mathop {CH}\limits^ \bullet C{H_3}$
$(2)$ (fig.)
$(3)$ $\mathop {C{H_2}}\limits^ \bullet - CH{(C{H_3})_2}$
$(4)$ $\mathop {C{H_2}}\limits^ \bullet - C{H_3}$