MCQ
Reaction of phenol with chloroform/sodium hydroxide to give $o$-hydroxy benzaldehyde involves the formation of
- ✓Dichloro carbene
- BTrichloro carbene
- CChlorine atoms
- DChlorine molecules
$O{H^ - } + CHC{l_3}$⇌ $HOH + :CCl_2^ - \to C{l^ - } + :CC{l_2}$
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$\begin{array}{*{20}{c}}{CHO}\\|\\{HCOH}\\|\\{HOCH}\\|\\{HCOH}\\|\\{C{H_2}OH}\\I\end{array}$ $\begin{array}{*{20}{c}}{CHO}\\|\\{HCOH}\\|\\{HCOH}\\|\\{HOCH}\\|\\{C{H_2}OH}\\{II}\end{array}$ $\begin{array}{*{20}{c}}{CHO}\\|\\{HCOH}\\|\\{HCOH}\\|\\{HCOH}\\|\\{C{H_2}OH}\\{III}\end{array}$

