Question
Read the text carefully and answer the questions:
Different organisations collect the data and analyse it quantitatively. During one such analysis some mistake crept in. The result given was that mean and variance of 100 observations as 40 and 5.1 but later on rechecking it was found that one observation was mistakenly taken as 50 instead of 40 .
(a) What is incorrect sum of variates?
(b) What is correct sum of observations?
(c) What is incorrect $\Sigma x^{2}$ ?
OR
What is corrected variance?

Answer

(i) Mean $=40, \mathrm{n}=100$, sum $=100 \times 40=4000$
(ii) Corrected sum $=4000-50+40=3990$
(iii) $\sigma^{2}=\frac{\Sigma x^{2}}{n}-\left(\frac{\Sigma x}{n}\right)^{2}$
$\Rightarrow(5.1)^{2}=\frac{\Sigma x^{2}}{100}-(40)^{2}$
$\Rightarrow(26.01+1600) 100=\Sigma x^{2}$
OR
Corrected $\Sigma x^{2}=162601-(50)^{2}+(40)^{2}$
$=162601-2500+1600=161701$
Corrected $\sigma^{2}=\frac{161701}{100}-(39.9)^{2}$
$=1617.01-1592.01=25$
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In XI standard, teacher was discussing about Spearman's Rank Correlation Coefficient in Statistics. Following points were discussed in the class about the same topic:
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When we are finding correlation between two qualitative characteristics, say, beauty and intelligence, we take recourse to using rank correlation coefficient. Rank correlation can also be applied to find the level of agreement (or disagreement) between two judges so far as assessing a qualitative characteristic is concerned. As compared to product moment correlation coefficient, rank correlation is easier to compute, it can also be advocated to get a first hand impression about the correlation between a pair of variables. Spearman's rank correlation coefficient is given by
$r _{ S }=1-\frac{6 \Sigma d^2}{n\left(n^2-1\right)}$
where,
d = difference between ranks of corresponding x and y
n = number of pairs of values (x,y) in the data
When the rank are repeated, the Spearman's rank correlation coefficient formula is given by
$r _{ S }=1-\frac{6\left[\Sigma d^2+\frac{\left(m_1^3-m_1\right)}{12}+\frac{\left(m_2^3-m_2\right)}{12}+\ldots \ldots\right]}{n\left(n^2-1\right)}$
where, $m _1, m_2 \ldots$, are the number of repetitions of ranks and $\frac{m_1^3-m_1}{12} \ldots$ their corresponding correlation factors.
For example: Ranks obtained by 10 students are given below:

34789
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(a) Find the value of $\Sigma d$?
(b) Find the value $\Sigma d^2$?
(c) What is the value of $n^2$ in the given data?
OR
What is rank correlation of the given data?

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A mobile number is having 10 digits. It is not just a group of numbers strung out at random. All mobile numbers have 3 things in common, a 2-digit Access code (AC), a 3-digit provider code (PC), and a 5 digit subscriber code (SC). AC code and PC code are fixed, then
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OR
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