Question
Reduce $\frac{-45}{30}$ to the standard form.
✓
Answer
Here, $\frac{-45}{30}=\frac{-45 \div 3}{30 \div 3}=\frac{-15}{10}=\frac{-15 \div 5}{10 \div 5}=\frac{-3}{2}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
A tin of oil weights $16.8\ kg.$ What is the weight of $45$ such tins of oil?
→Find the product: $54.5 \times 1.76$
→A rectangular field is $48m$ long and $12m$ wide. How many right triangular flower beds can be laid in this field, if sides including the right angle measure $2m$ and $4m,$ respectively$?$
→Add the following: $7 a b c,-5 a b c, 9 a b c,-8 a b c$
→Find the cost of painting a circular slogan of diameter 21 cm , If rate of painting is ₹ $20/m ^2$.
→Subtract - 254 from the sum of -127 and 243.
Express the number as a product of power of prime factor: $432$
→In Figure. state the three pairs of equal parts in $\triangle\text{ABC}$ and $\triangle\text{EOD}.$
Is $\triangle\text{ABC}\cong\triangle\text{EOD}?$ Why?
→Is $\triangle\text{ABC}\cong\triangle\text{EOD}?$ Why?
Multiply the following fractions: $7 \frac{5}{9} \times 1 \frac{1}{2}$
→Find the values of $n$ in the following:
$5^{2 n} \times 5^3=5^{11}$
→$5^{2 n} \times 5^3=5^{11}$