Question
Reduce the following rational expression to its lowest form
$
\frac{x^2-1}{x^2+x}
$

Answer

$\begin{aligned} & \frac{x^2-1}{x^2+x} \\ & =\frac{(x+1)(x-1)}{x(x+1)} \\ & =\frac{x-1}{x}\end{aligned}$

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