Question
Reduce the following fractions into its simplest form:
$\frac{48}{60}$
$\frac{48}{60}$
✓
Answer
Here, numerator $= 84$ and denominator $= 98$
Factors of $84$ are $1, 2, 3, 4, 6, 7, 12, 14, 21, 42$ and $84$
Factors of $98$ are $1, 2, 7, 14, 49$ and $98$
Common factors of $84$ and $98$ are $1, 2, 7$ and $14$
$H.C.F.$ of $84$ and $98$ is $14$
$\therefore\frac{48}{60}=\frac{48\div12}{60\div12}=\frac{4}{5}$
Hence, the simplest form of $\frac{48}{60}$ is $\frac{4}{5}$.
Factors of $84$ are $1, 2, 3, 4, 6, 7, 12, 14, 21, 42$ and $84$
Factors of $98$ are $1, 2, 7, 14, 49$ and $98$
Common factors of $84$ and $98$ are $1, 2, 7$ and $14$
$H.C.F.$ of $84$ and $98$ is $14$
$\therefore\frac{48}{60}=\frac{48\div12}{60\div12}=\frac{4}{5}$
Hence, the simplest form of $\frac{48}{60}$ is $\frac{4}{5}$.
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