Question
Reduce the following fractions to the lowest terms:$\frac{296}{481}$
✓
Answer
$\frac{296}{481}$ To reduce the given fraction to its lowest terms, we will divide the numerator and the denominators by their $HCF. $ Now, we will find the $HCF$ of $296$ and $481.$ 
$\therefore HCF = 37$ Dividing the numerator and the denominators by the $HCF$,
we get: $\frac{296\div37}{481\div37}=\frac{8}{13}$
$\therefore HCF = 37$ Dividing the numerator and the denominators by the $HCF$,
we get: $\frac{296\div37}{481\div37}=\frac{8}{13}$
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