Question
Subtract $8\frac13$ from $\frac{100}{9}$
✓
Answer
We have, $\frac{100}{9}-8\frac{1}{3}$$=\frac{100}{9}-\frac{8\times3+1}{3}$
$\because$ Mixed fraction = Improper fraction $=\frac{\text{Whole number}\times\text{denominator}+\text{Numerator}}{\text{Denominator}}$
$=\frac{100}{9}-\frac{25}{3}=\frac{100\times1}{9\times1}-\frac{25\times3}{3\times3}$[$\because$ $LCM$ of $9$ and is $9$, so convert each fraction to an equivalent fraction with denominator $9$]
$=\frac{100}{9}-\frac{75}{9}=\frac{25}{9}=2\frac79$
$\because$ Mixed fraction = Improper fraction $=\frac{\text{Whole number}\times\text{denominator}+\text{Numerator}}{\text{Denominator}}$
$=\frac{100}{9}-\frac{25}{3}=\frac{100\times1}{9\times1}-\frac{25\times3}{3\times3}$[$\because$ $LCM$ of $9$ and is $9$, so convert each fraction to an equivalent fraction with denominator $9$]
$=\frac{100}{9}-\frac{75}{9}=\frac{25}{9}=2\frac79$
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