Question
Reduce the given equation into the intercept form and find the intercept on the axis.
3x + 2y - 12 = 0

Answer

Here 3x + 2y - 12 = 0
$\Rightarrow$ 3x + 2y = 12
$\Rightarrow \frac{{3x}}{{12}} + \frac{{2y}}{{12}} = 1 \Rightarrow \frac{x}{4} + \frac{y}{6} = 1$
which is required intercept form.
Comparing it with $\frac{x}{a} + \frac{y}{b} = 1$, we have
a = 4 and b = 6

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