MCQ
Regarding catalytic cycle of an enzyme action, select the correct sequential steps :

$A$. Substrate enzyme complex formation.

$B$ Free enzyme ready to bind with another substrate.

$C$. Release of products.

$D$. Chemical bonds of the substrate broken.

$E$. Substrate binding to active site.

Choose the correct answer from the options given below :

  • A
    $A, E, B, D, C$
  • B
    $B, A, C, D, E$
  • C
     $E, D, C, B, A$
  • $E, A, D, C, B$

Answer

Correct option: D.
$E, A, D, C, B$
d
The correct answer is option ($4$) which is $E, A, D, C, B$.

The catalytic cycle of an enzyme action can be described in the following steps.

($1$) The binding of the substrate induces the enzyme to alter its shape, fitting more tightly around the substrate.

($2$) The active site of the enzyme, now in close proximity of the substrate breaks the chemical bonds of the substrate and the new enzyme-product complex is formed.

($3$) The enzyme releases the products of the reaction and the free enzyme is ready to bind to another molecule of the substrate and run through the catalytic cycle once again.

($4$) First, the substrate binds to the active site of the enzyme, fitting into the active site.

Options ($1$), ($2$) and ($3$) are incorrect as the steps mentioned are in the wrong sequence.

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