MCQ
Resolving power of a microscope depends upon
- AWavelength of light used, directly
- ✓Wavelength of light used, inversely
- CFrequency of light used
- DFocal length of objective
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$x = 0.01\cos \left( {\pi \,t + \frac{\pi }{4}} \right)$
The frequency of the motion will be
$\left(\frac{1}{4 \pi \varepsilon_{0}}=9 \times 10^{\circ} \frac{ Nm ^{2}}{ C ^{2}}\right.$ and speed of $1 ight$ $\left.=3 \times 10^{8}\, ms ^{-1}\right)$