Question
Reverse break down voltage for silicon diode is $6\ V$ for a particular doping concentration and forward break down voltage is $0.3\ V$ then find approximate current through battery in the given circuit....$Amp$

Answer

$i_1=\frac{9.7}{10} =0.97$

$i_2=\frac{4}{10} =0.4$

$i_1+i_2 =0.4+0.97$

$=1.37$

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