Question
Rewrite the following frequency distribution by stating class length and Mid Value of each class :
| Class | 0-99 | 100-299 | 300-499 | 500-749 | 750-899 | 900-999 |
| Frequency | 10 | 12 | 14 | 16 | 8 | 10 |
= 0.5 from the lower limit of each class and adding it to the upper limit of each class. we yet lower boundary point and upper boundary point respectively for each class, which is shown in the table on page 28.
= 49.5
= 199.5
= 399.5
= 624.5
= 824.5
= 949.5