Question
Rewrite the following rational numbers in the simplest form.
$\frac{-8}{6}$
$\frac{-8}{6}$
✓
Answer
Given, $\frac{-8}{6}$
$\because 6=2 \times 3$ and $8=2 \times 2 \times 2$
$\therefore HCF$ of 8 and $6=2$
On dividing the numerator and denominator by 2,
we get
$\frac{-8}{6}=\frac{-8÷2}{6÷2}=\frac{-4}{3}$
Hence, the simplest form of $\frac{-8}{6}$ is $\frac{-4}{3}$.
$\because 6=2 \times 3$ and $8=2 \times 2 \times 2$
$\therefore HCF$ of 8 and $6=2$
On dividing the numerator and denominator by 2,
we get
$\frac{-8}{6}=\frac{-8÷2}{6÷2}=\frac{-4}{3}$
Hence, the simplest form of $\frac{-8}{6}$ is $\frac{-4}{3}$.
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