MCQ
${\rm{cosec }}A - 2\cot 2A\cos A = $
- ✓$2\sin A$
- B$\sec A$
- C$2\cos A\cot A$
- DNone of these
$= \frac{1}{{\sin A}} - \frac{{2\cos A\cos 2A}}{{\sin 2A}}$
$ = \frac{1}{{\sin A}} - \frac{{2\cos A\cos 2A}}{{2\sin A\cos A}} $
$= \frac{{1 - \cos 2A}}{{\sin A}} $
$= \frac{{2{{\sin }^2}A}}{{\sin A}}$
$ = 2\sin A$.
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