In $S{c}$, the $e^{-}$ configuration is $3 d^{1} 4 s^{2}$
wheareas in $Z{n}$ configuration is $3 d^{10} 4 s^{2}$
$\therefore \,\ln \,Z{n}$, the $3 d$ leaving completely filled, its not a transtion element.
$(1)\,Cu^{2+}$ $(2)\,Ti^{4+}$ $(3)\, Co^{2+}$ $(4)\,Fe^{4+}$