MCQ
$(\sec 2A + 1){\sec ^2}A = $
  • A
    $\sec A$
  • B
    $2\sec A$
  • C
    $\sec 2A$
  • $2\sec 2A$

Answer

Correct option: D.
$2\sec 2A$
d
(d) $(\sec 2A + 1){\sec ^2}A $

$= \left( {\frac{{1 + {{\tan }^2}A}}{{1 - {{\tan }^2}A}} + 1} \right)\,(1 + {\tan ^2}A)$

$ = \frac{{2\,(1 + {{\tan }^2}A)}}{{1 - {{\tan }^2}A}}$

$= 2\sec 2A.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free