( A + A - 1)( A - A + 1) - 2 A = - Vidyadip

MCQ

$(\sec A + \tan A - 1)(\sec A - \tan A + 1) - 2\tan A = $

A
$\sec A$
B
$2\sec A$
✓
$0$
D
$1$

✓

Answer

Correct option: C.

$0$

c
(c) $(\sec A + \tan A - 1)(\sec A - \tan A + 1) - 2\tan A$

$ = ({\sec ^2}A - {\tan ^2}A) + \sec A + \tan A - \sec A$$ + \tan A - 1 - 2\tan A = 0$

$( \because {\sec ^2}A - {\tan ^2}A = 1)$

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