- A$C_4H_9 -$ has four alkyl groups
- B$C_5H_{11} -$ has eight alkyl groups
- C$C_3H_7$ has two alkyl groups
- ✓All of these
$C_5H_{11}$ $ \Rightarrow $ $C-C-C-C-C$ $\begin{array}{*{20}{c}}
{C - C - C - C - C} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|}
\end{array}$ $\begin{array}{*{20}{c}}
{C - C - C - C - C} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\begin{array}{*{20}{c}}
{C\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C - C - C - C - }
\end{array}$ $\begin{array}{*{20}{c}}
{C\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,} \\
{C - C - C - C} \\
{|\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,C\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{ - C - C - C - C}
\end{array}$ $\begin{array}{*{20}{c}}
{C\,\,\,} \\
{|\,\,\,\,} \\
{C - C - C - } \\
{|\,\,\,\,} \\
{\,C\,\,\,\,}
\end{array}\,$ $\begin{array}{*{20}{c}}
{C\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,} \\
{C - C - C - C} \\
{\,\,\,\,\,\,\,\,\,\,|}
\end{array}$
$C_3H_7$ $ \Rightarrow $ $C-C-C-$ $\begin{array}{*{20}{c}}
{C - C - C} \\
|
\end{array}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$I . C H_{3}^{+}$ $II.$ $H_{3} O ^{+}$ $III.$ $N H_{3}$ $I V\,\, C H_{3}^{-}$
$MnO_4^ - + 5F{e^{2 + }} + 8{H^ + } \to M{n^{2 + }} + 5F{e^{3 + }} + 4{H_2}O$
Here $10\,ml$ of $0.1\,M$ $KMn{O_4}$ is equivalent to
