MCQ
Select the correct statement
- A$C_4H_9 -$ has four alkyl groups
- B$C_5H_{11} -$ has eight alkyl groups
- C$C_3H_7$ has two alkyl groups
- ✓All of these
$C_5H_{11}$ $ \Rightarrow $ $C-C-C-C-C$ $\begin{array}{*{20}{c}}
{C - C - C - C - C} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|}
\end{array}$ $\begin{array}{*{20}{c}}
{C - C - C - C - C} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\begin{array}{*{20}{c}}
{C\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C - C - C - C - }
\end{array}$ $\begin{array}{*{20}{c}}
{C\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,} \\
{C - C - C - C} \\
{|\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,C\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{ - C - C - C - C}
\end{array}$ $\begin{array}{*{20}{c}}
{C\,\,\,} \\
{|\,\,\,\,} \\
{C - C - C - } \\
{|\,\,\,\,} \\
{\,C\,\,\,\,}
\end{array}\,$ $\begin{array}{*{20}{c}}
{C\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,} \\
{C - C - C - C} \\
{\,\,\,\,\,\,\,\,\,\,|}
\end{array}$
$C_3H_7$ $ \Rightarrow $ $C-C-C-$ $\begin{array}{*{20}{c}}
{C - C - C} \\
|
\end{array}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$3 \mathrm{PbCl}_2+2\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \rightarrow \mathrm{Pb}_3\left(\mathrm{PO}_4\right)_2+6 \mathrm{NH}_4 \mathrm{Cl}$
If $72 \mathrm{mmol}$ of $\mathrm{PbCl}_2$ is mixed with $50 \mathrm{mmol}$ of$\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4$, then amount of $\mathrm{Pb}_3\left(\mathrm{PO}_4\right)_2$ formed is......... mmol. (nearest integer)
$(a)$ $CO < C{O_2} < CO_3^{2 - }$ $ \Rightarrow $ Bond length
$(b)$ ${O_2} < {O_3} < O_2^{ - 2}$ $ \Rightarrow $ Bond length
$(c)$ ${N_2} < N_2^ + $ $ \Rightarrow $ Bond energy