MCQ
Select the elements belonging to same group from the following list :-
- ✓$Z = 12, 38, 4, 88$
- B$Z = 9, 16, 3, 35$
- C$Z = 5, 11, 27, 19$
- D$Z = 24, 47, 42, 55$
because every period is having certain intervals such as 2,8,8,18,18,32,31 to 1 to 7 periods respectively.
so that if we add these numbers to element atomic number we can get next element of the same group.a)
$4,4+8,12+8,20+18,38+18,56+32$
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(A) $\mathrm{Cu}^{+} \rightarrow \mathrm{Cu}^{2+}+\mathrm{Cu}$
(B) $3 \mathrm{MnO}_4^{2-}+4 \mathrm{H}^{+} \rightarrow 2 \mathrm{MnO}_4^{-}+\mathrm{MnO}_2+2 \mathrm{H}_2 \mathrm{O}$
(C) $2 \mathrm{KMnO}_4 \rightarrow \mathrm{K}_2 \mathrm{MnO}_4+\mathrm{MnO}_2+\mathrm{O}_2$
(D) $2 \mathrm{MnO}_4^{-}+3 \mathrm{Mn}^{2+}+2 \mathrm{H}_2 \mathrm{O} \rightarrow 5 \mathrm{MnO}_2+4 \mathrm{H}^{+}$
Choose the correct answer from the options given below:
$4C{a_5}{(P{O_4})_3}F + 18Si{O_2} + 30C \to 3{P_4} + 2Ca{F_2} + 18CaSi{O_3} + 30CO$
To make it chiral compound the attack should be on which carbon atom