MCQ
Sets $A$ and $B$ have $3$ and $6$ elements respectively. What can be the minimum number of elements in $A \cup B$
  • A
    $3$
  • $6$
  • C
    $9$
  • D
    $18$

Answer

Correct option: B.
$6$
b
(b) $n(A \cup B) = n(A) + n(B) -n(A \cap B) $ = $3 + 6 - n(A \cap B)$

Since, maximum number of elements in $A \cap B = 3$

$\therefore $ Minimum number of elements in $A \cup B = 9 - 3 = 6$.

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