Question
Short-Answer Question:
Write the zeros of the quadratic polynomial $f(x) = 6x^2 - 3$
Write the zeros of the quadratic polynomial $f(x) = 6x^2 - 3$
✓
Answer
To find the zeros of the quadratic polynomial we will equate f(x) to 0 f(x) = 0
$\Rightarrow 6x^2 - 3 = 0 \Rightarrow 3(2x^2 - 1) = 0$
$\Rightarrow 2x^2 - 1 = 0$
$\Rightarrow 2x^2 = 1$
$\Rightarrow\text{x}^2=\frac{1}{2}$
$\Rightarrow\text{x}=\pm\frac{1}{\sqrt2}$
Hence, the zeros of the quadratic polynomial $f(x) = 6x^2 - 3 $are $\frac{1}{\sqrt2},\ -\frac{1}{\sqrt2}.$
$\Rightarrow 6x^2 - 3 = 0 \Rightarrow 3(2x^2 - 1) = 0$
$\Rightarrow 2x^2 - 1 = 0$
$\Rightarrow 2x^2 = 1$
$\Rightarrow\text{x}^2=\frac{1}{2}$
$\Rightarrow\text{x}=\pm\frac{1}{\sqrt2}$
Hence, the zeros of the quadratic polynomial $f(x) = 6x^2 - 3 $are $\frac{1}{\sqrt2},\ -\frac{1}{\sqrt2}.$
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