Question
Short note on: Glycogen
✓
Answer
→"The carbohydrates are stored in animal body as glycogen."
→It is also known as animal starch because its structure is similar to amylopectin and is rather more highly branched.
→It is present in liver, muscles and brain.
→When the body needs glucose, enzymes break down glycogen into glucose.
→It is also known as animal starch because its structure is similar to amylopectin and is rather more highly branched.
→It is present in liver, muscles and brain.
→When the body needs glucose, enzymes break down glycogen into glucose.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
How will you carry out the following conversion?
Write note on enthalpy of atomization of trasition metals.
What is the effect on the $H _2 SO _4$ present in a lead storage cell if it is used continously?
→A first order gas reaction A2B2(g) → 2A(g) + 2B(g) at the temperature 400°C has the rate constant K = 2.0 × 10-4 s-1 . What percentage of A2B2 is decomposed on heating for 900 seconds.
How will you distinguish 1° and 2° hydroxyl groups present in glucose? Explain with reactions.
What are nucleic acids? Mention their two important functions.
Explain what is meant by:
- A peptide linkage.
- A glycosidic linkage.
For the first order thermal decomposition reaction, following data were obtained:
Calculate the rate constant.
(Given : log 2 = 0.301, log 3 = 0.4771, log 4 = 0.6021)
→| C2H5Cl(g) | $\xrightarrow{\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }}$ | C2H4(g) + HCl(g) |
| Time/sec | Total pressure/atm | |
| 0 | 0.30 | |
| 300 | 0.50 |
(Given : log 2 = 0.301, log 3 = 0.4771, log 4 = 0.6021)
Explain the following items:
Avitaminosis.
Avitaminosis.
Consider the decomposition of hydrogen peroxide in alkaline medium which is catalysed by iodide ions.
$\text{2H}_2\text{O}_2\xrightarrow{\text{OH}^-}2\text{H}_2\text{O}+\text{O}_2$
This reaction takes place in two step as given below:
Step-I $\text{H}_2\text{O}_2+\text{I}^-\rightarrow\text{H}_2\text{O}_2+\text{IO}^-\text{ (slow)}$
Step-II $\text{H}_2\text{O}_2+\text{IO}^-\rightarrow\text{H}_2\text{O}_2+\text{I}+\text{O}_2\text{ (fast})$
→$\text{2H}_2\text{O}_2\xrightarrow{\text{OH}^-}2\text{H}_2\text{O}+\text{O}_2$
This reaction takes place in two step as given below:
Step-I $\text{H}_2\text{O}_2+\text{I}^-\rightarrow\text{H}_2\text{O}_2+\text{IO}^-\text{ (slow)}$
Step-II $\text{H}_2\text{O}_2+\text{IO}^-\rightarrow\text{H}_2\text{O}_2+\text{I}+\text{O}_2\text{ (fast})$
- Write the rate law expression and determine the order of reaction w.r.t. H2O2.
- What is the molecularity of each individual step?