Question
Show that : $2 \sin ^{-1}\left(\frac{3}{5}\right)=\tan ^{-1}\left(\frac{24}{7}\right)$
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$\int x^2 \sin 3 x d x$
$\hat{i}+3 \hat{j}+5 \hat{k}$ and $7 \hat{i}+9 \hat{j}+11 \hat{k}$ Find the position vector of the fourth vertex.
$x^3+x^2 y+x y^2+y^3=81$
$\sec ^{-1} x+\operatorname{cosec}^{-1} x=\frac{\pi}{2} \ldots[$ for $|x| \geq 1]$