Question
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$(4 p q+3 q)^2-(4 p q-3 q)^2=48 p q^2$
$(4 p q+3 q)^2-(4 p q-3 q)^2=48 p q^2$
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Answer
$(4 p q+3 q)^2-(4 p q-3 q)^2=48 p q^2$
$\text { LHS }=(4 p q+3 q)^2-(4 p q-3 q)^2$
$=4(4 p q)(3 q)\left[\because(a+b)^2-(a+b)^2=4 a b\right]$
$=48 p q^2$
$=\text { RHS }$
$\text { LHS }=(4 p q+3 q)^2-(4 p q-3 q)^2$
$=4(4 p q)(3 q)\left[\because(a+b)^2-(a+b)^2=4 a b\right]$
$=48 p q^2$
$=\text { RHS }$
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