Question
Show that $8^n$ cannot end with the digit zero for any natural number $n$.

Answer

The prime factorization should have 2 and 5 as a common factor for a number to end with the digit zero.
$8^n=(2 \times 2 \times 2)^n$ does not have 5 in its prime factorization.
Hence, $8^n$ cannot end with the digit zero for any natural number $n$.

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