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Algebraic Expressions and Identities — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSAlgebraic Expressions and Identities2 Marks
Question
Show that: $(a - b)(a + b) + (b - c)(b + c) + (c - a)( c + a) = 0$
✓

Answer

$(a - b)(a + b) + (b - c)(b + c) + (c - a)( c + a) = 0$
$LHS = (a - b)(a + b) + (b - c)(b + c) + (c - a)( c + a)$
$=a^2-b^2+b^2-c^2+c 2-a^2$
$= 0$
$= RHS$
Because $LHS$ is equal to $RHS$, the given equation is verified.

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