Question
Solve:
$ 64-(a+1)^2 $
$ 64-(a+1)^2 $
✓
Answer
$ 64-(a+1)^2 $
$ =(8)^2-(a+1)^2 $
$ =[8-(a+1)][8+(a+1)] $
$ =(8-a-1)(8+a+1) $
$ =(7-a)(9+a) $
$ =(8)^2-(a+1)^2 $
$ =[8-(a+1)][8+(a+1)] $
$ =(8-a-1)(8+a+1) $
$ =(7-a)(9+a) $
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